Human Molecular Genetics by Strachan Tom & Read Andrew

Human Molecular Genetics by Strachan Tom & Read Andrew

Author:Strachan, Tom & Read, Andrew [Strachan, Tom]
Language: eng
Format: epub
ISBN: 9780429827464
Publisher: CRC Press
Published: 2018-12-19T16:00:00+00:00


Unaffected

Affected

Genotype

AA

Aa

aa

H–W frequency

p 2

2 pq

q 2 = 1/2000

q 2 = 1/2000, therefore q = √(1/2000) × 1/45. p = 1 − q = 44/45, so 2 pq = 2 × 44/45 × 1/45 = 1/23.

The fiancé has a 1 in 23 chance of being a carrier. For the woman, her risk follows from simple Mendelian segregation ( Figure 12.1 ).

Figure 12.1 Carrier risk for the unaffected sister of a person with cystic fibrosis. She has an affected brother, so both her parents must be carriers (there is a negligible rate of fresh mutation for cystic fibrosis). The genotype probabilities for their children are as shown. The chance the unaffected sister is a carrier is not 1 in 2; it is 2 in 3 because we know she has one of the genotypes in the shaded box.

The chance that both partners are carriers is 1/23 × 2/3, and the risk that any child of theirs would be affected is 1/23 × 2/3 × 1/4 = 1 in 138. Should they risk having children? That is their own personal decision. The job of the genetic counselor is to explain the risk, to make sure they fully understand it, to help them arrive at their own decision, and to support them in that decision, whatever it is. The counselor might point out that any pregnancy is at 1–2% risk of producing an abnormal baby, so the extra risk due to cystic fibrosis should be seen in that context, but it is not for the counselor to tell them what to do.

For X-linked loci (see Figure 5.5 ), males, being hemizygous (having only one allele), are A or a with frequencies p and q , respectively, whereas females can be AA , Aa , or aa ( Figure 12.2 ). So, for example, if a survey shows that one man in 12 has X-linked red–green color blindness, we can see directly that q = 1/12, and so we would predict that one woman in 144 would be affected, and 22 in 144 would be carriers. In reality the genetics of red–green color blindness is rather more complicated, but hopefully this simplified example serves present purposes.



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